Saturday, November 29, 2008

UCB chem1a 14

K${}_{SP}$ = [*(aq)] / [*(s)==const] = [*(aq)] Soluability Products
Solubility 's' K${}_{SP} = s^2$
PbI${}_2$(s)$\frac{right}{left} Pb${}^{2+} + 2$I${}^-$
s 2s
K${}_{SP} = s (2s)^2 = 4 s^3$View

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