Becquerel = [s^-1]
@equilibrium ... rates of forward RxN and the rates of backward RxN are the same
A + B ⇔ C + D
-> @ k${}_{1}$[A][B]
<- @ k${}_{-1}$[C][D]
K = [C] [D] / [A][B]
then @ equilibrium k${}_{1}$ / k${}_{-1}$ = K
"elementary reaction" ... rate law can be written as eq. " the reaction order, the molecularity and the stoichiometric coefficient are the same"
"Molecularity"
Lec 32 | MIT 5.111 Principles of Chemical Science, Fall 2005
@equilibrium ... rates of forward RxN and the rates of backward RxN are the same
A + B ⇔ C + D
-> @ k${}_{1}$[A][B]
<- @ k${}_{-1}$[C][D]
K = [C] [D] / [A][B]
then @ equilibrium k${}_{1}$ / k${}_{-1}$ = K
"elementary reaction" ... rate law can be written as eq. " the reaction order, the molecularity and the stoichiometric coefficient are the same"
"Molecularity"
Lec 32 | MIT 5.111 Principles of Chemical Science, Fall 2005
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